30500=(x^2)+x

Solution for 30500=(x^2)+x equation:

30500=(x^2)+x

We move all terms to the left:

30500-((x^2)+x)=0

We get rid of parentheses

-x^2-x+30500=0

We add all the numbers together, and all the variables

-1x^2-1x+30500=0

a = -1; b = -1; c = +30500;
Δ = b2-4ac
Δ = -12-4·(-1)·30500
Δ = 122001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{122001}}{2*-1}=\frac{1-\sqrt{122001}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{122001}}{2*-1}=\frac{1+\sqrt{122001}}{-2}
$